Cross-sectional study

Apical Aneurysms and Mid–Left Ventricular Obstruction in Hypertrophic Cardiomyopathy

JACC Cardiovasc ImagingPublished

  • Cross-sectional study
  • 3 dedicated programs
  • echocardiography and CMR

Authors' conclusion

The great majority (95%) of patients in the continuum of apical aneurysms have associated mid-LV obstruction.

Study context

Population
Patients with hypertrophic cardiomyopathy (HCM) apical left ventricular (LV) aneurysms from 3 dedicated programs
Participants
108 / 63 / 47
Exposure
HCM apical aneurysm patients vs normal controls and apical-mid HCM controls without aneurysms
  • Aneurysmn = 108
  • Normal controlsn = 63reference
  • Apical-mid HCM controlsn = 47reference
Outcome
Frequency of mid-LV obstruction in HCM apical aneurysms

Main finding

As reported in the abstract

Mid-LV obstruction with mid-LV complete systolic emptying

Aneurysm

95%

103 of 108

Observational data: associations, not effects.

Further findings

Doppler findings among patients with mid-LV obstruction

Midsystolic Doppler signal void (marker of complete flow cessation)
84%
Doppler systolic gradients ≥30 mm Hg
19%

Relative mid-LV hypokinesia without obstruction

Patients with relative hypokinesia in mid-LV without obstruction
5 (5%)

Short-axis (SAX) papillary muscle areas: aneurysm vs elevated LV velocities without aneurysm

Aneurysm: SAX papillary muscle (PM) area, median (IQR)
3.00 cm² (2.38-3.70 cm²)
Elevated LV velocities, no aneurysm: SAX PM area, median (IQR)
2.45 (1.81-2.95 cm²)
SAX PM areas 22% greater with aneurysm
P = 0.004

Mid-LV obstruction aneurysm vs all control groups (SAX and PM measures)

SAX systolic areas smaller
P < 0.007
Percent SAX area change greater
P < 0.005
PM areas larger
P < 0.003
Diastolic PM areas/SAX diastolic areas greater
P < 0.005

Original publication

Apical Aneurysms and Mid–Left Ventricular Obstruction in Hypertrophic Cardiomyopathy. JACC Cardiovasc Imaging. Published 11 January 2023. doi:10.1016/j.jcmg.2022.11.013

Summarised from the published abstract; every number is checked against it